32^2+60^2=c^2

Solution for 32^2+60^2=c^2 equation:

32^2+60^2=c^2

We move all terms to the left:

32^2+60^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+4624=0

a = -1; b = 0; c = +4624;
Δ = b2-4ac
Δ = 02-4·(-1)·4624
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-136}{2*-1}=\frac{-136}{-2}
=+68
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+136}{2*-1}=\frac{136}{-2}
=-68
$